The following table shows the marks scored by 80 students in an examination:
Marks | Less than 5 | Less than 10 | Less than 15 | Less than 20 | Less than 25 | Less than 30 | Less than 35 | Less than 40 |
Number of eggs | 3 | 10 | 25 | 49 | 65 | 73 | 78 | 80 |
Calculate the mean marks correct to 2 decimal places.
We will find the mean marks using step - deviation method, where A = Assumed mean and h = length of class interval.
Here, let A = 17.5 and h = 5
Since, the class intervals are less - than type, we’ll first convert it into exclusive type.
WEIGHT(G) | MID - POINT(xi) | DEVIATION(di) di = xi – 17.5 | NUMBER OF EGGS(fi) | ui = di/h | fiui |
0 - 5 | 2.5 | - 15 | 3 | - 3 | - 9 |
5 - 10 | 7.5 | - 10 | 7 | - 2 | - 14 |
10 - 15 | 12.5 | - 5 | 15 | - 1 | - 15 |
15 - 20 | 17.5 = A | 0 | 24 | 0 | 0 |
20 - 25 | 22.5 | 5 | 16 | 1 | 16 |
25 - 30 | 27.5 | 10 | 8 | 2 | 16 |
30 - 35 | 32.5 | 15 | 5 | 3 | 15 |
35 - 40 | 37.5 | 20 | 2 | 4 | 8 |
TOTAL | 80 | 17 |
We have got
A = 17.5, h = 5, Σfi = 80 & Σfiui = 17
∵ mean is given by
⇒
⇒
Thus, mean marks correct to 2 decimal places are 18.56.