Solve each of the following systems of equations by using the method of cross multiplication:
7x – 2y = 3, 22x – 3y = 16.

Question

Solve each of the following systems of equations by using the method of cross multiplication: 7x – 2y = 3, 22x – 3y = 16.

Philoid · Accepted Answer

We have,

7x – 2y – 3 = 0 …(i)

22x – 3y – 16 = 0 …(ii)

From equation (i), we get a₁ = 7, b₁ = - 2 and c₁ = - 3

And from equation (ii), we get a₂ = 22, b₂ = - 3 and c₂ = - 16

Using cross multiplication,

⇒

⇒ and

⇒ x = 1 and y = 2

Thus, x = 1, y = 2

Solve each of the following systems of equations by using the method of cross multiplication:7x – 2y = 3, 22x – 3y = 16.