If the combination is connected to a battery of emf 12 V and negligible internal resistance, obtain the potential drop across each resistor.

Let the current flowing in the circuit be I.

Electromotive force EMF, (E) = 12V

Total resistance in the circuit R = 6 Ω

According to Ohm ’s law, V = IR

Potential drop across 2 Ω resistor = 2 × 2 = 4Volt, as V = I × R by Ohm ’s Law

Potential drop across 1 Ω resistor = 2 × 1 = 2Volt

Potential drop across 3 Ω resistor = 2 × 3 = 6Volt