A closely wound solenoid of 800 turns and area of cross section 2.5 × 10–4 m2 carries a current of 3.0 A. Explain the sense in which the solenoid acts like a bar magnet. What is its associated magnetic moment?
Given:
Number of turns, N = 800
Area of cross-section, A = 2.5 × 10-4 m2
Current, I = 3A
The solenoid acts like a bar magnet because the magnetic axis of the solenoid is along its length, which is analogous to the magnetic axis of Bar magnet.
We know that,
Magnetic moment, M = N × I × A …(1)
Now putting the values in equation 1, we get
M = 800 × 3A × 2.5 × 10-4m2
M = 0.6 JT-1