A short bar magnet has a magnetic moment of 0.48 J T^–1. Give the direction and magnitude of the magnetic field produced by the magnet at a distance of 10 cm from the centre of the magnet on (a) the axis, (b) the equatorial lines (normal bisector) of the magnet.

Question

Philoid · Accepted Answer

Magnetic moment of the bar magnet, M = 0.48 J T⁻¹

(a) Distance, d = 10 cm = 0.1 m

The magnetic field at distance d, from the centre of the magnet on the axis is given by the relation:

μ₀ = permeability of the free space = 4 x 10^-7

⇒ B₁ = 0.96 x 10^-4 T

∴ B₁ = 0.96 G

The magnetic field is along the S − N direction.

(b) The magnetic field at a distance of 10 cm i.e., d = 0.1 m on the equatorial line of the magnet is given as:

= 0.48 G

The magnetic field is along the N − S direction.

A short bar magnet has a magnetic moment of 0.48 J T–1. Give the direction and magnitude of the magnetic field produced by the magnet at a distance of 10 cm from the centre of the magnet on (a) the axis, (b) the equatorial lines (normal bisector) of the magnet.