A 60 μF capacitor is connected to a 110 V, 60 Hz A.C. supply. Determine the rms value of the current in the circuit.
Given: capacitance = 60 μF = 60 × 10-6 F
Voltage V = 110 V
Frequency f = 60 Hz
The diagram is:
Capacitive reactance is given by the following relation:
Xc = 1/ωC
Substituting ω = 2πv in the above formula, we get
Xc = 1/2πvC
Substituting the values, we get
⇒
Now, the root mean square value of the current can be calculated as follows:
Irms = V/Xc
Irms = 110V × 2 × 3.14 × (60Hz) × 60 × 10-6(F)
On calculating, we get
Irms = 2.49 A