Now assume that the straight wire carries a current of 50 A and the loop is moved to the right with a constant velocity, v = 10 m/s.

Calculate the induced emf in the loop at the instant when x = 0.2 m.


Take a = 0.1 m and assume that the loop has a large resistance.


The emf induced in the coil is given as:


e = B’ av


e =


substituting the given values in above relation, we get


e =


On calculating, we get


e = 5 × 10-5V


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