A circus tent is cylindrical to a height of 4 m and conical above it. If its diameter is 105 m and its slant height is 40 m, the total area of canvas required is
Given: A circus tent is cylindrical to a height of 4 m and conical above it.
Its diameter is 105 m and its slant height is 40 m.
CSA of the Cylinder is given by: 2πrh (here, r and h are radius and height respectively)
Let V1 be the CSA of the cylindrical part of tent
∴ V1 = 2πrh
⇒ V1 = 2 × π × 
× 4 = 1320cm2 (here diameter is 105 cm, ∴ radius = 
cm)
CSA of the cone is given by: πrl (here, r and l are radius and slant height respectively)
Let V2 be the CSA of the conical part of tent
∴ V2 = πrl
⇒ V2 = π × 
× 40 = 6600 cm2 (here diameter is 105 cm, ∴ radius = 
cm)
∴ Total area of the canvas is V1 + V2
∴ V1 + V2 = 1320 + 6600 = 7920cm2
∴ Total area of the canvas is: 7920 cm2