If sin θ = cos (θ – 45°), where θ is acute, find the value of θ.
We are given that: sin θ = cos (θ – 45°)
∴We can rewrite it as: cos (90° – θ ) = cos (θ – 45°)
On comparing both sides, we get,
90° – θ = θ – 45°
⇒ θ + θ = 90° + 45°
⇒ 2θ = 135°
⇒ θ = 65.5°