An organic compound A (molecular formula C₂H₄O₂) reacts with Na metal to form a compound B and evolves a gas which burns with a pop sound. Compound A on treatment with an alcohol C in the presence of a little of concentrated sulphuric acid forms a sweet-smelling compound D (molecular formula C₃H₆O₂). Compound D on treatment with NaOH solution gives back B and C. Identify A, B, C and D.
A is ethanoic acid (CH₃COOH) ; B is sodium ethanoate (CH₃COONa); C is methanol (CH₃OH) and D is methyl ethanoate (CH₃COOCH₃).
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1

Question

An organic compound A (molecular formula C₂H₄O₂) reacts with Na metal to form a compound B and evolves a gas which burns with a pop sound. Compound A on treatment with an alcohol C in the presence of a little of concentrated sulphuric acid forms a sweet-smelling compound D (molecular formula C₃H₆O₂). Compound D on treatment with NaOH solution gives back B and C. Identify A, B, C and D.

A is ethanoic acid (CH₃COOH) ; B is sodium ethanoate (CH₃COONa); C is methanol (CH₃OH) and D is methyl ethanoate (CH₃COOCH₃).

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Philoid · Accepted Answer

A is ethanoic acid (CH₃COOH) ; B is sodium ethanoate (CH₃COONa); C is methanol (CH₃OH) and D is methyl ethanoate (CH₃COOCH₃).