Let A = {1, 2, 3}, B = {4, 5, 6, 7} and let f = {(1, 4), (2, 5), (3, 6)} be a function from A to B. Show that f is one-one.
It is given that A = {1, 2, 3}, B = {4, 5, 6, 7}
f: A → B is defined as f = {(1, 4), (2, 5), (3, 6)}
Therefore, f(1) = 4, f(2) = 5, f(3) = 6
We can see that the images of distinct elements of A under f are distinct.
Therefore, function f is one- one.