State with reason whether following functions have inverse
h: {2, 3, 4, 5} → {7, 9, 11, 13} with
h = {(2, 7), (3, 9), (4, 11), (5, 13)}
It is given that h: {2, 3, 4, 5} → {7, 9, 11, 13} with
h = {(2, 7), (3, 9), (4, 11), (5, 13)}
We can see that all distinct elements of the set (2, 3, 4, 5} have distinct images under h.
⇒ h is one–one.
Also, h is onto since for every element of the set {7, 9, 11, 13},
there exists an element x in the set {2, 3, 4, 5} such that h(x) = y.
Therefore, h is a one–one and onto function.
Therefore, h has an inverse.