Find the values of x, y and z from the following equations:


Since, the given matrices are equal, their corresponding elements are also equal.

Comparing the corresponding element, we have:


x + y = 6, xy = 8, 5 + z = 5


Now, 5 + z = 5


=> z = 0


We know that (x –y)2 = (x + y)2 – 4xy


=> (x –y )2 = 36 -32 = 4


=> x – y = �2


Now, when x – y = 2, x + y = 6, we get, x = 4 and y = 2


And, when x – y = -2, x + y = 6, we get, x = 2 and y = 4


Therefore, x = 4, y = 2 and z = 0 or x = 2, y = 4 and z = 0


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