Find the values of x, y and z from the following equations:

Since, the given matrices are equal, their corresponding elements are also equal.

Comparing the corresponding element, we have:

x + y = 6, xy = 8, 5 + z = 5

Now, 5 + z = 5

=> z = 0

We know that (x –y)² = (x + y)² – 4xy

=> (x –y )² = 36 -32 = 4

=> x – y = �2

Now, when x – y = 2, x + y = 6, we get, x = 4 and y = 2

And, when x – y = -2, x + y = 6, we get, x = 2 and y = 4

Therefore, x = 4, y = 2 and z = 0 or x = 2, y = 4 and z = 0