Using elementary transformations, find the inverse of each of the matrices.


First of all we need to check whether the matrix is invertible or not. For that-

For the inverse of a matrix A to exist,


Determinant of A ≠ 0


Here A = (1)(3) – (-1)(2) = 5


So the matrix is invertible.


Now to find the inverse of the matrix,


We know AA-1 = I


Let’s make augmented matrix-


[ A : I ]



Apply row operation- R2 R2 – 2R1



Apply row operation- R2 R2/5



Apply row operation- R1 R1 + R2



The matrix so obtained is of the form –


[ I : A-1 ]


Hence inverse of the given matrix-



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