Differentiate the functions given in w.r.t. x.

cos x . cos 2x . cos 3x


Given: cos x . cos 2x . cos 3x


Let y= cos x . cos 2x . cos 3x


Taking log on both sides, we get


log y = log(cos x . cos 2x . cos 3x)


log y = log(cos x) + log(cos 2x) + log(cos 3x)


Now, differentiate both sides with respect to x







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