Find a point on the curve y = (x – 2)2 at which the tangent is parallel to the chord joining the points (2, 0) and (4, 4).
We know that if a tangent is parallel to the chord joining the points (2,0) and (4,4), then
Slope of the tangent = slope of the curve………….(1)
And, the slope of the curve =
Now, slope of the tangent to the given curve at a point (x,y) is:
Now, from (1) we have,
2(x -2) = 2
⇒ x-2 = 1
⇒ x =3
So, when x = 3 then y = (3-2)2 = 1
Therefore, required points are (3,1).