Find the equations of the tangent and normal to the given curves at the indicated points:


x = cos t, y = sin t at t=π/4


It is given that equation of curve is x = cost, y = sint



On differentiating with respect to x, we get




Therefore, the slope of the tangent at ) is -1.


When


Then, the equation of the tangent is is


y – = -1(x – )


x + y -- = 0


x + y - = 0


Then, slope of normal at


=


Now, equation of the normal at


y – = 1(x –)


x = y


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