If the radius of a sphere is measured as 7 m with an error of 0.02 m, then find the approximate error in calculating its volume.
Let r be the radius of the sphere and Δr be the error in measuring the radius.
Now, it is given that r = 7m and Δr = 0.02m
We know that volume of sphere (V) = 
Now, 
= (4πr2)Δr
= 4π (72)(0.02)m3
= 3.92π m3
Therefore, the approximate error in calculating its volume is 3.92π m3.
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