A window is in the form of a rectangle surmounted by a semi - circular opening.
The total perimeter of the window is 10 m. Find the dimensions of the window to admit maximum light through the whole opening.
Let x and y be the length and breadth of the rectangular window.
Radius of the semi - circular opening = ![]()
It is given that the perimeter of the window is 10m.
⇒ x + 2y + ![]()
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Therefore, Area of the window (A) is given by
= ![]()
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Now, 
 , then
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=0
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Then, when x = 
 then 
 < 0.
Therefore, by second derivative test, the area is maximum when length
x = 
 m.
Now, y = ![]()
Therefore, the required dimensions of the window to admit maximum light is given by length = 
 m and breadth =
m.