The normal at the point (1,1) on the curve 2y + x 2 = 3 is

Question

Philoid · Accepted Answer

It is given that the equation of curve is 2y + x² = 3

Differentiating w.r.t. x, we get,

The slope of the normal to the given curve at point (1,1) is

Then, the equation of the normal to the curve at (1,1) is

⇒ y – 1 =1(x - 1)

⇒ y - 1 = x – 1

⇒ x – y = 0

The normal at the point (1,1) on the curve 2y + x2 = 3 is