Prove that
Let Δ =
Applying Elementary Row Transformations
R2→ R2 – 2R1
Δ =
R3→ R3 – 3R1
R3→ R3 – 3R2
Expanding Along C1, we have
Δ = 1 (1 × 1 – 0 × (2 + p)) – 0 + 0
Δ = 1 – 0
Δ = 1
Hence, the given result is proved