If show that A2 – 5A + 7I =0.
To prove: A2 – 5A + 7I = 0
Given: A =
L.H.S: A2 – 5A + 7I
R.H.S = 0
I =
Calculating value of A2:
A2 = A.A
=
=
=
=
Substituting value in L.H.S we get,
= A2 – 5A + 7I
.
= 0 = R.H.S
L.H.S = R.H.S
Hence A2 – 5A + 7I = 0 is proved.