If the solubility product of CuS is 6 × 10^-16, calculate the maximum molarity of CuS in aqueous solution.

The Solubility product of CuS (ksp) = 6 × 10^-16

CuS → Cu ^{+ +} + S^2-

Let the s be solubility of CuS in mol/L

Ksp = [ Cu ^{+ +} ][S²]

Ksp = solubility product

6 × 10^-16 = s × s = s²

⇒ S = 2.45 × 10^-8 mol/L

Hence, the maximum molarity of CuS in an aqueous solution is 2.45 × 10^-8 mol/L