Calculate the emf of the cell in which the following reaction takes place:

Ni(S) + 2Ag+ (0.002M) Ni2+ (0.160 M) + 2Ag(s)


Given that


Given:


[Ag+] = 0.002 M


[Ni2+] = 0.160 M


n = 2


(n = moles of e- from balanced redox reaction)


E0cell= 1.05 V


Now, using the Nernst equation we get,






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