Suggest a way to determine the Λ°m value of water


Λ°m (H2O) = Λ°m(H+) + Λ°m(OH-)


For calculation purpose, Λ°m(Na+) and Λ°m(Cl-) are added and subtracted.


Λ°m (H2O) = Λ°m(H+) + Λ°m(OH-)+ Λ°m(Na+) - Λ°m(Na+) + Λ°m(Cl-) - Λ°m(Cl-)


Λ°m (H2O) = Λ°m(HCl) + Λ°m(NaOH) - Λ°m(NaCl)


If we know the other values, Λ°m (H2O) can be calculated.


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