Write the Nernst equation and emf of the following cells at 298 K:
(i) Mg(s)|Mg2+ (0.001M)||Cu2+ (0.0001 M)|Cu(s)
(ii) Fe(s)|Fe2+ (0.001M)||H+ (1M)|H2(g)(1bar)| Pt(s)
(iii) Sn(s)|Sn2+ (0.050 M)||H+ (0.020 M)|H2(g) (1 bar)|Pt(s)
(iv) Pt(s)|Br2(l)|Br–(0.010 M)||H+ (0.030 M)| H2(g) (1 bar)|Pt(s).
Ecell = ?
(i) Mg + Cu2 + → Mg2 + + Cu (n = 2)
E0Cu2 + /Cu + = 0.34V
E0Mg2 + /Mg = - 2.37 V
E0cell = E0R - E0L
E0cell = 0.34 - ( - 2.37) → Equation 1
Using Nernst equation, we get,
→ Equation 2
Substituting Equation 1 in equation 2, we get,
∴ Ecell = 0.34 - ( - 2.37) -
= 2.71 -
= 2.71 - 0.02955
∴ Ecell = 2.68 V
The e.m.f of the cell, Ecell is 2.68 V
ii) Fe + 2H + → Fe2 + + H2 (n = 2)
E0H + /H2 = 0 V
E0Fe2 + /Fe = - 0.44 V
E0cell = E0R - E0L
E0cell = 0 - ( - 0.44) → Equation 1
Using Nernst equation, we get,
→Equation 2
Substituting Equation 1 in equation 2, we get,
∴ Ecell = 0 - ( - 0.44) -
= 0.44 -
= 0.44 - 0.0887
∴ Ecell = 0.5287 V
The e.m.f of the cell, Ecell is 0.5287 V
iii) Sn + 2H + → Sn2 + + H2 (n = 2)
E0H + /H2 = 0 V
E0Sn2 + /Sn = - 0.14V
E0cell = E0R - E0L
E0cell = 0 - ( - 0.14) → Equation 1
Using Nernst equation, we get,
→Equation 2
Substituting Equation 1 in equation 2, we get,
∴ Ecell = 0 - ( - 0.14) -
= 0.14 -
= 0.14 - 0.0295×2.0969
∴ Ecell = 0.08 V
The e.m.f of the cell, Ecell is 0.08 V
iv) 2Br - + 2H + → Br2 + H2 (n = 2)
E0H + /H2 = 0 V
E0Br2/Br - = 1.08V
E0cell = E0R - E0L
E0cell = 0 - (1.08) → Equation 1
Using Nernst equation, we get,
→Equation 2
Substituting Equation 1 in equation 2, we get,
∴ Ecell = 0 - (1.08) -
= - 1.08 -
= - 1.08 - 0.208
∴ Ecell = 1.288 V
The e.m.f of the cell, Ecell is 1.288 V