The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 S cm–1. Calculate its molar conductivity.


Given -


Molarity, C = 0.20 M


Electrolytic conductivity of a solution, κ = 0.0248 S cm–1


Molar conductivity = ?


Molar conductivity, m = S cm2 mol-1



m = 124 S cm2 mol-1


Molar conductivity(m) of 0.20 M solution of KCl at 298 K is 124 S cm2 mol-1


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