The resistance of a conductivity cell containing 0.001M KCl solution at 298 K is 1500 Ω. What is the cell constant if the conductivity of 0.001M KCl solution at 298 K is 0.146 × 10^–3 S cm^–1.

Question

The resistance of a conductivity cell containing 0.001M KCl solution at 298 K is 1500 Ω. What is the cell constant if the conductivity of 0.001M KCl solution at 298 K is 0.146 × 10 –3 S cm –1 .

Philoid · Accepted Answer

Given -

Resistance of a conductivity cell, R = 1500

Electrolytic conductivity of a solution, κ = 0.146 × 10^–3 S cm^–1

Cell constant = ?

Conductivity, κ =

Cell constant = κ × R

= 0.146 × 10^–3 S cm^–1×1500

Cell constant = 0.219 cm^-1

The cell constant of the cell containing 0.001M KCl solution at 298 K is 0.219 cm^-1

The resistance of a conductivity cell containing 0.001M KCl solution at 298 K is 1500 Ω. What is the cell constant if the conductivity of 0.001M KCl solution at 298 K is 0.146 × 10–3 S cm–1.

The resistance of a conductivity cell containing 0.001M KCl solution at 298 K is 1500 Ω. What is the cell constant if the conductivity of 0.001M KCl solution at 298 K is 0.146 × 10^–3 S cm^–1.