How much charge is required for the following reductions:

(i) 1 mol of Al3 + to Al?


(ii) 1 mol of Cu2 + to Cu?


(iii) 1 mol of MnO4 to Mn2+ ?


(i) The electrode reaction is given as,


Al3 + (aq) + 3e - Al(s)


The quantity of charge required for the reduction of 1 mol of Al3+ = 3F


= 3×96487 C


= 289461 C


(ii) The electrode reaction is given as,


Cu2 + (aq) + 2e - Cu(s)


The quantity of charge required for the reduction of 1 mol of Cu2+ = 2F


= 2×96487 C


= 192974 C


(iii) The electrode reaction is given as,


MnO4 Mn2 +


i.e., Mn7 + + 5e - Mn2 +


The quantity of charge required for the reduction of 1 mol of Mn7+ = 5F


= 5×96487 C


= 482435 C


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