The conversion of molecules X to Y follows second order kinetics. If concentration of X is increased to three times how will it affect the rate of formation of Y ?

Let the reaction be X→Y

As, this reaction follows second order kinetics, the rate of the reaction will be,

Rate = k(X)² → Equation 1

Since the concentration of X is increased three times, Equation 1

will become,

Rate = k(3X)²

= k × 9(X)²

∴ The rate of formation of Y will become 9 times.

Thus, the rate of formation of Y will become 9 times