The conversion of molecules X to Y follows second order kinetics. If concentration of X is increased to three times how will it affect the rate of formation of Y ?


Let the reaction be XY


As, this reaction follows second order kinetics, the rate of the reaction will be,


Rate = k(X)2 Equation 1


Since the concentration of X is increased three times, Equation 1


will become,


Rate = k(3X)2


= k × 9(X)2


The rate of formation of Y will become 9 times.


Thus, the rate of formation of Y will become 9 times


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