A reaction is second order with respect to a reactant. How is the rate of reaction affected if the concentration is

(i) doubled (ii) reduced to half

Let suppose reaction

A ⇒ B;

having rate law, Rate = K [A]²

(i) If the concentration of A is doubled then the rate will affect by the square of concentration i.e. rate will become 2² = 4 times.

(ii) If the concentration of A is halved then the rate will affect the square of concentration i.e (1/2)² = 1/4 times.

(i) Rate becomes 4 times of initial Rate (ii) Rate becomes 1/4 times of initial Rate