The reaction between A and B is first order with respect to A and zero order with respect to B.Phil. in the blanks in the following table:


Experiment



[A]/mol L-1



[B]/mol L-1



Initial rate/mol L-1 min-1



I



0.1



0.1



2.0 × 10-2



II



-



0.2



4.0 × 10-2



III



0.4



0.4



-



IV



-



0.2



2.0 × 10-2



As reaction is first order with respect to A and zero Order with respect to B. Then changing the concentration of B won’t affect the rate of reaction and increasing concentration of A ‘n’ times will increase the rate by ‘n’ times. By this logic lets fill the table- In first blank space concentration of A will be 0.2 mol L-1 because the rate is doubled. In second blank space, Rate will be 8 × 10-2mol L-1min-1 because the concentration of A is increased 4 Times. In third blank space concentration of A will be 0.1 mol L-1 because the rate is same as in experiment I.


Experiment



[A]/mol L-1



[B]/mol L-1



Initial rate/mol L-1 min-1



I



0.1



0.1



2.0 × 10-2



II



0.2



0.2



4.0 × 10-2



III



0.4



0.4



8.0 × 10-2



IV



0.1



0.2



2.0 × 10-2




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