The decomposition of hydrocarbon follows the equation

k = (4.5 × 10¹¹s^–1) e^-28000K/T. Calculate E_a.

The given equation is

k = (4.5 x 10¹¹ s^-1) e^{-28000 K/T} (i)

Comparing, Arrhenius equation

k = Ae ^-E_a^/RT (ii)

We get, E_a / RT = 28000K / T

⇒ E_a = R x 28000K

= 8.314 J K^-1mol^-1 × 28000 K

= 232792 J mol^–1 or 232.792 kJ mol^–1