Predict the number of unpaired electrons in the square planar Pt[(CN)₄]^2- ion.

In Pt[(CN)₄]^2- ion:

Overall charge balance:

X + 4(-1) = -2

X = + 2.

The oxidation state of Pt is + 2.

Since CN^- is a strong field ligand, it causes pairing of the unpaired electrons.

Therefore, now the 2 unpaired electrons from 5d orbital get paired and it undergoes dsp² hybridisation. It forms square planar geometry. Since all the electrons are paired,

No. of unpaired electrons = 0.