If then
First of all we have to consider,
and
By simplifying above equations, we get:
3 (2x + y + 2) = 5 (3x – y + 1)
6x + 3y + 6 = 15x – 5y + 5
9x – 8y = 1 …(i)
And, 6 (3x – y + 1) = 3 (3x + 2y + 1)
18x – 6y + 6 = 9x + 6y + 3
3x – 4y = – 1 …(ii)
Now, multiplying (ii) by 2 and then subtracting it from (i) we get:
9x – 6x = 1 + 2
∴ x = 1
Putting the value of x in (ii), we get
3 × 1 – 4y = – 1
∴
Hence, option A is correct