If the lines given by 3x + 2ky = 2 and 2x + 5y + 1 = 0 are parallel then the value of k is
We have,
3x + 2ky – 2 = 0
And, 2x + 5y + 1 = 0
Here, a1 = 3, b1 = 2k and c1 = – 2
a2 = 2, b2 = 5 and c2 = 1
∴
And,
We know that, for the system having parallel lines we must have:
Hence, option D is correct