Solve each of the following quadratic equations:
abx2 + (b2 - ac)x - bc = 0
abx2 + (b2 - ac)x - bc = 0
abx2 + (b2 - ac)x - bc = 0
abx2 + b2x - acx - bc = 0
bx (ax + b) - c (ax + b) = 0 taking bx common from first two terms and –c from last two
(ax + b) (bx - c) = 0
(ax + b) = 0 or (bx - c) = 0
Hence the roots of equation are 
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