For what values of k, the equation kx2 - 6x - 2 = 0 has real roots?
Given the equation kx2 - 6x - 2 = 0 has real roots
a = k b = - 6 c = - 2
Thus D = b2 - 4ac ≥0
( - 6)2 - 4.k. - 2 ≥0
36 + 8k ≥0
8k≥ - 36
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For what values of k, the equation kx2 - 6x - 2 = 0 has real roots?
Given the equation kx2 - 6x - 2 = 0 has real roots
a = k b = - 6 c = - 2
Thus D = b2 - 4ac ≥0
( - 6)2 - 4.k. - 2 ≥0
36 + 8k ≥0
8k≥ - 36