x2 – 4ax + 4a2 – b2 = 0
Using splitting middle term, the middle term of the general equation
is divided in two such values that:
Product = a.c
For the given equation ![]()
=
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And either of their sum or difference = b
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Thus the two terms are ![]()
Sum = ![]()
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Product =
using ![]()
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x[x-(2a + b)]-(2a-b)[x-(2a + b)] = 0
[x-(2a-b)][x-(2a + b)] = 0
[x-(2a-b)] = 0 or [x-(2a + b)] = 0
x = (2a-b) or x = (2a + b)
Hence roots of equation are x = (2a - b) or x = (2a + b)