The circumference of a circle is 22 cm. Find the area of its quadrant.

Given:

Circumference of circle = 22 cm

Let the radius of the circle be ‘r’.

∵ Circumference of circle = 2πr

∴ 22 = 2 × π × r

⇒ 22 = 2 × × r

⇒ 22 × × = r or = r

or r =

∵ Area of circle = πr^{2}

∴ Area of its quadrant = πr^{2}

=

=

__Hence the area of the quadrant of the circle is__ __cm.__

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