The circumference of a circle is 22 cm. Find the area of its quadrant.
Given:
Circumference of circle = 22 cm
Let the radius of the circle be ‘r’.
∵ Circumference of circle = 2πr
∴ 22 = 2 × π × r
⇒ 22 = 2 ×
× r
⇒ 22 ×
×
= r or
= r
or r = ![]()
∵ Area of circle = πr2
∴ Area of its quadrant =
πr2
= ![]()
= ![]()
Hence the area of the quadrant of the circle is
cm.