A path of 8 m width runs around the outside of a circular park whose radius is 17 m. Find the area of the path.



Given radius of circular park = R = 17 m


Width of the circular path outside the park = d = 8 m


Therefore, the radius of the outer circle = R’ = R + d


Outer radius = R’ = 17 + 8


R’ = 25 m


Area of inner circle = πR2 and,


Area of outer circle = πR’2


Area of path = Area of outer circle – Area of inner circle


= πR’2 – πR2 (put values of R’ & R)


= π(252) – π(172)


= π(252 – 172) (taking π common from R.H.S)


= π(625 – 289)



(put π = 22/7)


= 7392/7


= 1056 m2


The area of the path is 1056 m2.


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