In the given figure, an equilateral triangle has been inscribed in a circle of radius 4 cm. Find the area of the shaded region. [Take π = 3.14 and √3 = 1.73]

Radius of circle = R = 4 cm

OD perpendicular to AB is drawn

ΔABC is equilateral triangle,

∠A = ∠B = ∠C = 60°

∠OAD = 30°

OD/AO = sin 30°

AO = 4 cm

OD = 1/2 × 4 cm

OD = 2 cm

AD² = OA² – OD²

= 4² – 2² = 16 – 4 = 12 cm²

AD = 2√3 cm

AB = 2 × AD

= 2 × 2√3 cm = 4√3 cm

Area of triangle ABC = √3/4 × AB²

= √3/4 × 4√3 × 4√3

= 20.71 cm²

Area of circle = πR²

= 3.14 × 4 × 4 cm²

= 50.24 cm²

Area of shaded region = 29.53 cm²