If a pole 12 m high casts a shadow 4√3 m long on the ground then the sun's elevation is
Let AB be the pole and BC be its shadow. Join A and C. Given that, AB = 12m, BC = 4√3m. We get a right-angled triangle ∆ABC, right angled at B. ∠ACB is the angle of elevation of the sun. We will use the trigonometric ratio tan taking AB as the height and BC as the base.
In ∆ABC,
or,
since we know that tanθ is √3 whenever θ = 60°.
So, the correct option is (A).