D and E are points on the sides AB and AC respectively of a ΔABC such that DE || BC.

Find the value of x, when



AD = x cm, DB = (x - 2) cm,


AE = (x + 2) cm and EC = (x - 1) cm.


Given: AD = x cm,


DB = (x – 2) cm,


AE = (x + 2) cm and,


EC = (x – 1) cm


By applying Thale’s Theorem,



⇒


⇒ x(x – 1) = (x + 2)(x – 2)


⇒ x2 – x = x2 – 4


⇒ x = 4


Thus, x = 4 cm


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