Find the height of an equilateral triangle of side 12 cm.


Capture.PNG


Δ ABC is an equilateral triangle.


Also, BC = AB = AC = 12 cm


The AD is the altitude at BC. Therefore, D is the midpoint of BC.


Now, ΔADB and ΔADC are right-angled triangles.


Applying Pythagoras theorem,


AB2 = BD2 + AD2


(12) 2 = 62 + AD2


AD2 = 144 – 36 = 108


AD = 6√3 cm


12
1