If ΔABC ~ΔDEF such that 2AB = DE and BC = 6 cm, find EF.

Given: ABC ~DEF such that 2AB = DE and BC = 6 cm.

From SSS-similarity criterion,

We get

AB/DE = BC/EF

Substituting the given values,

AB/2AB = 6cm/EF

1/2 = 6cm/EF

EF = 2 × 6cm

EF = 12cm

12cm