The height of an equilateral triangle having each side 12 cm, is



Since Δ ABC is an equilateral triangle so the altitude (Height = h) from the C is the median for AB dividing AB into two equal halves of 6 cm each


Now there are two right angled Δs


h2 = a2 - 1/2 (AB) 2


h2 = (12)2 - 62


h = 6 √3

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