In a ΔABC, it is given that AD is the internal bisector of ∠A. If AB = 10 cm, AC = 14 cm and BC = 6 cm, then CD = ?
By internal angle bisector theorem, the bisector of vertical angle of a triangle divides the base in the ratio of the other two sides”
Hence in Δ ABC
⇒ 10x -84 + 14x = 0
⇒ x = CD = 3.5 cm