In ΔABC, it is given that AB = 9 cm, BC = 6 cm and CA = 7.5 cm. Also, ΔDEF is given such that EF = 8 cm and ΔDEF ~ ΔABC. Then, perimeter of ΔDEF is

Perimeter of Δ ABC = AB + BC + CA

= 9 + 6 + 7.5

= 22.5 cm

Since the Δ ABC ∼ DEF

= (ratio of perimeter of triangles is equal to the ratio of the sides of the triangle )

=

=

= 30 cm