Two poles of height 6 m and 11 m stand vertically upright on a plane ground. If the distance between their feet is 12 m then the distance between their tops is


Given: Height of pole 1 = 6 m

Height of pole 2 = 11 m


Distance between the feet of pole 1 and pole 2 = 12 m


To find: Distance between the tops of both the poles



Clearly, In ∆ ADE,


DE = 5 m


AD = 12 m


Also, ∠ADE = 90° [∵ Both the poles stand vertically upright]


∴ By applying Pythagoras theorem, we have


AE2 = AD2 + DE2


⇒ AE2 = (12)2 + (5)2 = 144 + 25 = 169


⇒ AE = √169 = 13 m

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